Question

Find the centroid of Triangle whose vertices are $A(1,2,3),B(2,-1,6),C(3,2,-3)$

• A. $(2,1,2)$
• B. $(2,-1,2)$
• C. $(-2,-2,-2)$
• D. $(1,2,1)$

Answer 1

The correct option is A $(2,1,2)$

Given points

$A(1,2,3),B(2,-1,6),C(3,2,-3)$

Centroid of triangle is given as $(\frac{x_1+x_2+x_3}{3},\frac{y_1+y_2+y_3}{3},\frac{z_1+z_2+z_3}{3})$

$(\frac{1+2+3}{3},\frac{2-1+2}{3},\frac{3+6-3}{3})$

$(\frac{6}{3},\frac{3}{3},\frac{6}{3})$

$⟹(2,1,2)$