Question

Find the chance of throwing six with a single die at least once in five trials.

Answer 1

Probability of getting six in single throw $=\frac{1}{6}$

Probability of not getting six in single throw $=1-\frac{1}{6}=\frac{5}{6}$

Probability of not getting six in all six throws $={\left(\frac{5}{6}\right)}^6$

Probability of getting at least one six $=1-$not getting six in all the throws

$\Rightarrow P\left(E\right)=1-{\left(\frac{5}{6}\right)}^6$