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Byju's Answer
Standard XII
Chemistry
Entropy
Find the chan...
Question
Find the change in entropy (in cal/k) of
1
mole of
O
2
gas (
C
v
=
5
/
2
R
), when it is
(a) heated from
300
K
to
400
K
isobarically
(b) heated from
300
K
to
400
K
isochorically (Given:
ln
3
=
1.1
,
ln
2
=
0.7
)
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Solution
In Isochoric process,
Δ
S
=
n
C
V
ln
(
T
2
T
1
)
⟹
Δ
S
=
1
×
5
2
R
×
ln
(
4
3
)
⟹
Δ
S
=
1.5
c
a
l
T
−
1
In Isobaric process,
Δ
S
=
n
C
P
ln
(
T
2
T
1
)
⟹
Δ
S
=
7
2
R
×
ln
(
4
3
)
⟹
Δ
S
=
2.1
c
a
l
T
−
1
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Similar questions
Q.
Two moles of an ideal gas
(
C
v
,
m
=
12.5
J
K
−
1
m
o
l
−
1
)
are at
300
K
and
5
d
m
3
. If the gas is heated to
600
K
and the volume changed to
10
d
m
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, calculate the entropy change.
(take ln2=0.7,
R
=
8.3
J
m
o
l
−
1
K
−
1
)
Q.
When two mole of an ideal gas
(
C
p
.
m
=
5
2
R
)
heated from
300
K
to
600
K
at constant pressure. The change in entropy of gas (
Δ
S
) is:
Q.
When two mole of an ideal
(
C
p
.
m
=
5
2
R
)
heated from 300 K to 600 K at constant pressure. The change in entropy of gas
Δ
S
is
Q.
1
mole of ideal monoatomic gas is heated by supplying
5
k
J
heat from a reservoir maintained at
400
K
from
300
K
to
400
K
. In the process volume of gas increased from
1
L
to
10
L
. Find
Δ
S
t
o
t
a
l
(in J/K-mol) in the process
Use:
ln
(
4
3
)
=
0.3
ln
10
=
2.3
,
R
=
8.3
J
/
K
−
m
o
l
and
ln
x
=
2.3
log
x
Q.
Molar heat capacity of an ideal gas at constant volume is given by
C
v
=
16.5
+
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−
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T
(in Joule). If 3.5 moles of this ideal gas are heated at constant volume from 300K to 400K the change in internal energy (in kJ) will be:
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