Find the change in internal energy in joules when 10 g of air is heated from $30^{\circ} C$ to $40^{\circ} C$ . Given $C_{v} = 0.172 k c a l / k g K$

Open in App

Solution

Mass of air, $m = 10 g = 0.01 k g$
Change in temperature, $Δ T = 40 - 30 = 10^{\circ} C = 10 K$
Heat capacity at constant volume, $C_{v} = 0.172 k c a l / k g K$
So, $Δ U = m C_{v} Δ T = 0.01 \times 0.172 \times 10 k c a l = 0.01 \times 0.172 \times 10 \times 4200 J = 72.24 J$

Suggest Corrections

Similar questions

10 g

30^{\circ} C

40^{\circ} C

(c_{v} = 0.172 k c a l / k g / K J = 4200 J / k c a l)

g

30^{\circ} C

40^{\circ} C

0^{o} C

5^{o} C

^{o} C

g^{- 1}

C^{- 1}

Find the change in the internal energy of a gas when it absorbs 80 calories of heat and performs work equal to 170 joules

Join BYJU'S Learning Program