Find the change in internal energy of 60 g of Argon gas when its change in temperature is 200 K. (Given degree of freedom of argon is 3 and its molar mass = 40 g/mole)
A
4800.3J
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B
3741.3J
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C
1250.4J
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D
3500.2J
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Solution
The correct option is B3741.3J Since, we know ΔU=f2nRdT where ΔU= internal energy of the gas n = number of moles of gas ∴n=6040=1.5mole We know, f = degree of freedom = 3 (Given) ΔU=32×1.5×8.314×ΔT So, ΔU=32×1.5×8.314×200