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Question

Find the change in internal energy of the system when a system absorbs 2 kcal of heat and at the same time does 500J of work

A
8200J
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B
7900J
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C
6400J
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D
5600J
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Solution

The correct option is B 7900J
Heat absorbed is dQ=2000 cal=200×4.18=8368J and the work done is dW=500J.

Using first law, we have dQdW=dU=8368500=78687900J

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