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Question

Find the change in pH when 0.01 mole CH3COONa is added to one litre of 0.01 M CH3COOH. pKa=4.74

A
3.27
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B
4.74
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C
1.37
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D
2.74
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Solution

The correct option is C 1.37
pH=12pKA12logC

12×4.7412log[102]=2.37+1=3.37

pH of buffer = pKA+log(Salt)(Acid)

pH of buffer = 4.74+log(0.01)(0.01) = 4.74

Change in pH = 4.74 − 3.37 = 1.37

Hence, correct option is C.

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