Find the change in range of a projectile if acceleration due to gravity changes by $d g$

d R = R \frac{d g}{g}

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d R = - \frac{R d g}{g}

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d R = \frac{R d g}{2 g}

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d R = - \frac{- R d g}{2 g}

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Solution

The correct option is D $d R = - \frac{R d g}{g}$
The horizontal range $R = \frac{u^{2} sin 2 θ}{g}$
differentiating with respect to g, $\frac{d R}{d g} = - \frac{u^{2} sin 2 θ}{g^{2}} = - \frac{R}{g}$
or $d R = - \frac{R d g}{g}$

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Find the change in range of a projectile if acceleration due to gravity changes by dg

The correct option is D dR=−RdggThe horizontal range R=u2sin2θgdifferentiating with respect to g, dRdg=−u2sin2θg2=−Rgor dR=−Rdgg

Find the change in range of a projectile if acceleration due to gravity changes by $d g$

The correct option is D $d R = - \frac{R d g}{g}$
The horizontal range $R = \frac{u^{2} sin 2 θ}{g}$
differentiating with respect to g, $\frac{d R}{d g} = - \frac{u^{2} sin 2 θ}{g^{2}} = - \frac{R}{g}$
or $d R = - \frac{R d g}{g}$