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Question

Find the change in the internal energy (in J) of 2 kg of water as it is heated from 0oCto4oC. The specific heat capacity of water is 4200 J/kgK and its densities at 0oC and 4oC are 999.9 kg/m3and1000 kg/m3 respectively. Atmospheric pressure = 105Pa.

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Solution

form the first law of thermodynamics
dQ=dU+dW
work done is not completely zero but it's magnitude is very small so it can be neglected,or we can find it applying isobaric process.
Q=mSΔT
Q1=2×4200×273=2293200 J
Q2=2×4200×277=2326800 J
now ΔU=Q2Q1=33600 J

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