Question

Find the charge appearing on capacitor of capacitance $4\mu F$ :

• A. $32\mu C$
• B. $96\mu C$
• C. $12\mu C$
• D. $4\mu C$

Answer 1

Answer: (A)

$32\mu C$

As the two capacitances are in series combination, so equivalent capacitance,$C_{equ}=\frac{8\times 4}{8+4}=\frac{32}{12}=\frac{8}{3}\mu F$
So, charge on $4\mu F,Q=C_{equ}\times V=\frac{8}{3}\times 12=32\mu C$