Question

Find the charge present on the capacitor C in the following circuit :

• A. $12\mu C$
• B. $14\mu C$
• C. $20\mu C$
• D. $18\mu C$

Answer 1

The correct option is D $18\mu C$

At steady state current will not flow in branch that contains capacitator ,so 6$\Omega$ and 2$\Omega$ will become in series so net current $\left(\frac{12}{6+2}\right)$

Resistor of 4$\Omega$ will become short circuited $I_{net}=\frac{3}{2}A$

Voltage across capacitor = Voltage across 6$\Omega$

$\frac{q}{C}=iR\frac{q}{2\times {10}^{-6}}=\frac{3}{2}\times 6q=18\times {10}^{-6}$

q = $=18\mu C$