Question

Find the charge stored in the capacitor.

Answer 1

In steady state current flows in lower loop of the circuit.

$i=\frac{30}{6+4}=3A$

Now, potential difference across capacitor $=$ potential difference across $4\Omega$ resistance.

$=iR$

$=\left(3\right)\left(4\right)=12V$

$\therefore q=CV=\left(2\mu F\right)\left(12V\right)$

$=24\mu C$