Find the charges on the three capacitors connected to a battery as shown in figure (31-E1). Take C1=2.0 μF, C2=4.0 μF, C3=6.0 μF and V=12 volts.
C1=2 μF, C2=4 μF,
C3=6 μF, V=12 V
Ceq=C1+C2+C3
=2+4+6
=12 μF=12×10−6 F
q1=12×2=24 μC,
q2=12×4=48 μC,
q3=12×6=72 μC