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Question

Find the charges on the three capacitors connected to a battery as shown in figure (31-E1) Take C1=2·0 μF, C2=4·0 μF, C3=6·0 μF and V=12 volts.

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Solution

The capacitances of three capacitors are C1= 2 μF, C2= 4 μF and C3= 6 μF and the voltage of the battery (V) is 12 V.
As the capacitors are connected in parallel, the equivalent capacitance is given by
Ceq = C1 + C2 + C3
= (2 + 4 + 6) μF = 12 μF = 12 × 10-6 F



Due to parallel connection, the potential difference across each capacitor is the same and is equal to 12 V.

Therefore, the charge on each capacitor can be calculated as follows:
The charge on the capacitor of capacitance C1= 2 μF is given by

Q1 = C1V = (2 × 10-6) × 12 C = 24 × 10-6 C = 24 μC

Similarly, the charges on the other two capacitors are given by
Q2 = C2V = (4 × 10-6) × 12 C = 48 × 10-6 C = 48 μC
and
Q3 = C3V = (6 × 10-6) × 12 C = 72 × 10-6 C = 72 μC

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