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Question

Find the circumcentre of a triangle whose vertex are (0,0),(4,0) and (0,6)

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Solution

Let A (0,0) B (4,0) and C (0,6)

AB has a constant ordinate and

hence t is on x axis (ordinate=0)

AC has a constant abscissa (=0)

Hence it is on y axis

ABAC

Hence the given triangle is a

right angled triangle ,at A

so, BC is the hypotenuse,

and circumferential is the midpoint
of the hypotenuse.

Hence . midpoint of BC

(4+02,0+62)

(42,62)=(2,3)

The circumcentre is (2,3)

1194444_1322371_ans_15ef24fdafdb41bf99f07b6def29f176.jpg

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