Find the circumference of the jogging track when two semicircles are joined at the edges of the rectangle as shown. (Take π = 3.14)

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Solution

Circumference of the jogging track = Circumference of a circle of diameter 5 cm + 10 cm + 10 cm

$= π \times 5 + 10 + 10$ cm
$= 3.14 \times 5 + 10 + 10$ cm
$= 15.7 + 10 + 10$ cm
$= 35.7$ cm

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Find the circumference of the jogging track when two semicircles are joined at the edges of the rectangle as shown. (Take π = 3.14)

Circumference of the jogging track = Circumference of a circle of diameter 5 cm + 10 cm + 10 cm =π×5+10+10 cm =3.14×5+10+10 cm =15.7+10+10 cm =35.7 cm

Circumference of the jogging track = Circumference of a circle of diameter 5 cm + 10 cm + 10 cm

$= π \times 5 + 10 + 10$ cm
$= 3.14 \times 5 + 10 + 10$ cm
$= 15.7 + 10 + 10$ cm
$= 35.7$ cm