Question

Find the co-ordinates of the centroid of the triangle whose vertices are (13, -4) , (3, 4) , (8, -3).
[2 Marks]

Answer 1

Here $x_1=13,x_2=3and{x}_3=8$
And $y_1=-4,y_2=4and{y}_3=-3$
[0.5 Marks]
Co-ordinates of centroid:
$(x,y)=(\frac{x_1+x_2+x_3}{3},\frac{y_1+y_2+y_3}{3})\left[1Mark\right]=(\frac{13+3+8}{3},\frac{-4+4-3}{3})=(\frac{24}{3},\frac{-3}{3})$
[1 Mark]
$\therefore$ Centriod of the triangle is (8, -1).

[0.5 Marks]