The correct option is D (−110,3710)
Equation of given line is y=3x+4
Let Q(x1,y1) be the foot of the perpendicular on the line.
⇒y1=3x1+4 ......(i)
Slope of given line is 3.
Slope of perpendicular PQ=−13
⇒y1−3x1−2=−13
⇒3y1=−x1+11 .....(ii)
Solving (i) and (ii), we get
x1=−110,y1=3710