Question

Find the co-ordinates of the point which divides the join of the point $(2,3)$ and $(6,8)$ externally in the ratio $4:3$.

Answer 1

Let the point $P(x,y)$ divide the line segment join f the point $(x_1,y_1),(x_2,y_2)=(2,3),(6,8)$

And divide in the ratio $m:n=4:3$

By section formula,

Coordinate are $x=\frac{m{x}_2-n{x}_1}{m-n}$ and $y=\frac{m{y}_2-n{y}_1}{m-n}$

Therefore,

$x=\frac{4\times 6-3\times 2}{4-3}=18$

$y=\frac{4\times 8-3\times 3}{4-3}=23$

So the points of divide $(18,23)$