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Question

Find the coefficient of x10 in the expansion of (1+x)2(1−x)3

A
40
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B
50
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C
60
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D
None of the above
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Solution

The correct option is D 40
(1+x)2.(1x)3
(1+2x+x2)(...............+3+81C8.x8+3+91C9.x9+3+101C10.x10..........)
So, to get coefficent ofx10
(..........................+(10C8+211C9+12C10).x10+.........................)
Hence the coefficent is 10C8+211C9+12C10=(40+110+60)=220

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