CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Find the coefficient of x10 in the expansion of (1+x)2(1−x)3

A
40
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
50
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
60
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
None of the above
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is D 40
(1+x)2.(1x)3
(1+2x+x2)(...............+3+81C8.x8+3+91C9.x9+3+101C10.x10..........)
So, to get coefficent ofx10
(..........................+(10C8+211C9+12C10).x10+.........................)
Hence the coefficent is 10C8+211C9+12C10=(40+110+60)=220

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Visualising the Coefficients
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon