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Question

Find the coefficient of :
x100 in the expansion of 35x(1x)2

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Solution

Given expression can be written as

(35x)(1x)2=
[1+2x+(2)(21)x22!.....+(2)(21)..(298)x9999!+(2)(21)...(299)x100100!]

coefficient of x100
=3.101!100!5.100!99!=303500=197


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