Find the coefficient of x16 in the expansion of (x2−2x)10.
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Solution
We have (x2−2x)10=x20(1−2x)10 and since x20 multiplies every term in the expansion of (1−2x)10, we have in this expansion to seek the coefficient of the term which contains 1x4 Hence the required coefficient 10C4(−2)4=10.9.8.71.2.3.4×16=3360