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Question

Find the coefficient of x16 in the expansion of (x22x)10.

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Solution

We have (x22x)10=x20(12x)10
and since x20 multiplies every term in the expansion of (12x)10, we have in this expansion to seek the coefficient of the term which contains 1x4
Hence the required coefficient 10C4(2)4=10.9.8.71.2.3.4×16=3360

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