wiz-icon
MyQuestionIcon
MyQuestionIcon
3
You visited us 3 times! Enjoying our articles? Unlock Full Access!
Question

Find the coefficient of x16 in the expansion of (x22x)10.

Open in App
Solution

We have (x22x)10=x20(12x)10
and since x20 multiplies every term in the expansion of (12x)10, we have in this expansion to seek the coefficient of the term which contains 1x4
Hence the required coefficient 10C4(2)4=10.9.8.71.2.3.4×16=3360

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Binomial Coefficients
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon