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Question

Find the coefficient of x2 in the expansion of e2x+3 as a series in powers of x.

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Solution

In the exponential series ex=1+x1!+x22!+x23!+...
Hence e2x+3=e3.e2x=e3[1+x1!+x22!+x23!+...]
Thus, the coefficient of x2 in the expansion of e2x+3 is e3.222!=2e3.

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