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Question

Find the coefficient of x2009 in the expansion of (1x)2008(1+x+x2)2007

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Solution

f(x)=(1x)2008×(1+x+x2)2007f(x)=(1x)1×((1x)(1+x+x2))2007f(x)=(1x)1×(1+x+x2xx2x3)2007f(x)=(1x)1×(1x3)2007f(x)=(1x3)2007x(1x3)2007Allthetermsintheexpansion(1x3)2007isintheformx3rAndinthex(1x3)2007isoftheformx3p+1So3r=2009or3p+1=2009Wherewedonotgetintegervaluesofr,p.Sothecoefficientofx2009is0

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