Find the coefficient of $x^{2} y^{5}$ in the expansion of $(3 + 2 x - y)^{10}$ .

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Solution

coeff of $x^{2} y^{5}$ in expansion of
$(3 + 2 x - y)^{10}$ is calculates by
multinational expansion
ie
$\frac{10!}{3^{3} (2)^{2} (- 1)^{5}} = \frac{- 10!}{27 \times 4}$
$= - 37800$ Ans

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