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Question

Find the coefficient of x4 in the expansion of (1+x)n(1x)n. Deduce that C2=C0C4C1C3+C2C2C3C1+C4C0, where, C stands for nCr.

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Solution

(1+x)n×(1x)n=[C0+C1x+C2x2+...+Cnxn]×[C0C1x+C2x2....+(1)nCnxn]

(1+x)n×(1x)n=(1x2)n=[C0C1x2+C2x4...+(1)nCnx2n].

C0C4C1C3+C2C2C3C1+C4C0=C2


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