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Question

Find the coefficient of x5 in (x+3)8.

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Solution

Here, general term of the expansion (x+3)8 is

Tr+1=8Cr(x)8r(3)r ...(i)

Now 8r=5r=85=3

Putting r=3 in (i)

T4=8C3x5(3)3

Coefficient of x5 on the expansion

(x+3)8=8C3.(3)3=1512

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