Find the coefficient of $x^{6}$ in the expansion of $(3 + 2 x)^{10}$ .

Open in App

Solution

The coefficient of $x^{6}$ in the expansion $(3 + 2 x)^{10}$ is
$^{10} C_{6} {.3}^{4} {.2}^{6}$
$=^{10} C_{4} {.3}^{4} {.2}^{6}$ [ Since $^{n} C_{r} =^{n} C_{n - r}$ for $n > 0, n - r > 0, r > 0$ ]
$= {210.3}^{4} {.2}^{6}$

Suggest Corrections

Similar questions

x^{6}

{(2 x^{2} - \frac{3}{x})}^{11}

x^{6}

(2 + 2 x)^{10}

x^{16}

(x^{2} - 2 x)^{1} 0

x^{16}

{(x^{2} - 2 x)}^{10}

x^{6}

(1 + 4 x^{2} + 10 x^{4} + 20 x^{6})^{- \frac{3}{4}}

Join BYJU'S Learning Program