wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Find the coefficient of x6 in the expansion of (2x2−3x)11:

A
42
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
59
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
44
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 0
Tr+1=11Cr(2x2)11r(3)(x)r
=11Crx222r211r(3)r
As coefficient of x is 6
223r=6
r=163 which is not possible.
Therefore , coefficient is 0

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
What is Binomial Expansion?
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon