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Question

Find the coefficient of x7 in (1−x+x2+x3)6

A
144
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B
144
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C
120
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D
120
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Solution

The correct option is D 144
(1xx2+x3)6=(1x)6(1x2)6=(6C06C1x+.....+6C6x6)(6C06C1x2+.....+6C6x12)
Now sufficient of x7 is 6C16C36C36C2+6C56C1

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