Find the coefficient of $x^{8}$ in the following expansion
$(1 + x) (1 + x^{2}) (1 + x^{3}) (1 + x^{4}) (1 + x^{5}) . . .$
$. . . . (1 + x^{98}) (1 + x^{99}) (1 + x^{100})$ .

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Solution

The correct option is C $6$

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Similar questions

x^{2^{m + 1}}

E =

\frac{1}{(1 + x) (1 + x^{2}) (1 + x^{4}) (1 + x^{8}) . . . . (1 + x^{2 m})} (| x | < 1)

\begin{matrix} Find the derivative of the function given by f (x) = (1 + x) (1 + x^{2}) (1 + x^{4}) (1 + x^{8}) and hence find f^{'} (1) . \end{matrix}

x^{9}

(1 + x) (1 + x^{2}) (1 + x^{3}) . . . . . (1 + x^{100})

x^{9}

(1 + x) (1 + x^{2}) (1 + x^{3}) \dots \dots . (1 + x^{100})

f (x) = (1 + x) (1 + x^{2}) (1 + x^{4}) (1 + x^{8}) . . . \infty

f (\frac{1}{2}) =

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