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Question

Find the coefficient of xn2 in
(nC0+nC1x+nC2x2.....nCnxn)×(nC0+nC1x+nC2x2.....nCnxn)


A

nC0×nCn2+nC1×nCn3.....nCnnC2

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B

nC0×nC2+nC1×nC3.....nCn2×nCn

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C

n2r=0nCr×nCn2r

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D

nr=0nCr×nCr1

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Solution

The correct option is C

n2r=0nCr×nCn2r


In the expansion of
(nC0+nC1x+nC2x2.....nCnxn)×(nC0+nC1x.....nCnxn)
We get the terms with xn2 when we multiply
(nC0 and nCn2xn2),(nC1x and nCn3xn3).....(nCn2xn2 and nC0)
From first sum and 2nd sum
⇒ The coefficient will be sum of each coefficient.
= nC0×nCn2+nC1×nCn3.....nCn2×nC0
This is what option (A) is. If we modify the terms using the property nCr=nCnr
We get, nC0nC2+nC1×nC3+.....nCn2×nC0
This is option (B)
Option (C) is the summation written with variable. When we expand (C) we get (B) and (A).


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