Find the coefficient of xn−2 in
(nC0+nC1x+nC2x2.....nCnxn)×(nC0+nC1x+nC2x2.....nCnxn)
In the expansion of
(nC0+nC1x+nC2x2.....nCnxn)×(nC0+nC1x.....nCnxn)
We get the terms with xn−2 when we multiply
(nC0 and nCn−2xn−2),(nC1x and nCn−3xn−3).....(nCn−2xn−2 and nC0)
From first sum and 2nd sum
⇒ The coefficient will be sum of each coefficient.
= nC0×nCn−2+nC1×nCn−3.....nCn−2×nC0
This is what option (A) is. If we modify the terms using the property nCr=nCn−r
We get, nC0nC2+nC1×nC3+.....nCn−2×nC0
This is option (B)
Option (C) is the summation written with variable. When we expand (C) we get (B) and (A).