wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Find the coefficient of xn2 in
(nC0+nC1x+nC2x2.....nCnxn)×(nC0+nC1x+nC2x2.....nCnxn)


A

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct options are
A


B


C


In the expansion of
(nC0+nC1x+nC2x2.....nCnxn)×(nC0+nC1x.....nCnxn)
We get the terms with xn2 when we multiply
(nC0 and nCn2xn2),(nC1x and nCn3xn3).....(nCn2xn2 and nC0)
From first sum and 2nd sum
⇒ The coefficient will be sum of each coefficient.
= nC0×nCn2+nC1×nCn3.....nCn2×nC0
This is what option (A) is. If we modify the terms using the property nCr=nCnr
We get, nC0nC2+nC1×nC3+.....nCn2×nC0
This is option (B)
Option (C) is the summation written with variable. When we expand (C) we get (B) and (A).


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
How to Expand?
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon