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Question

Find the coefficient of xr in the expansion of (1x)2(1+x)3

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Solution

The expression =(14x+4x2)(1+p1x+p2x2+...+prxr+...) suppose.
The coefficient of xr will be obtained by multiplying pr,pr1,pr2 by 1,4,4 respectively, and adding the results ; hence
the required coefficient =pr4pr1+4pr2
But pr=(1)r(r+1)(r+2)2
Hence the required coefficient
=(1)r(r+1)(r+2)24(1)r1r(r+1)2+4(1)r2(r1)r2
=(1)r2[(r+1)(r+2)+4r(r+1)+4r(r1)]
(1)r2(9r2+3r+2)

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