Find the coefficients of xnyn in the expansion of [(1 + x) (1 + y) (x + y)]n
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Solution
(1+x)n=C0+C1x+C2x2+....+Cnxn (y+1)n=C0yn+C1Yn−1C2Yn−2+..+Cn Note ( y + 1) (x+y)n=C0xn+C1xn−1y+C2xn−2y2+Cnyn If will be multiply them , each vertical column will be the term of xnyn ∴(1+x)n(1+y)n(x+y)n the coefficient of xnynis C30+C31+C32+...+C3n