Find the common difference for the arithmetic progression $3 + 2 \sqrt{2}, 3 + 4 \sqrt{2}, 3 + 6 \sqrt{2}, 3 + 8 \sqrt{2}$ .

3 + \sqrt{2}

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3

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\sqrt{2}

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2 \sqrt{2}

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Solution

The correct option is D $2 \sqrt{2}$
Common difference ( $d$ ) of an AP is the difference between any two consecutive terms of the AP.
Thus, the common difference of the given AP is
$d = (3 + 4 \sqrt{2}) - (3 + 2 \sqrt{2}) = 2 \sqrt{2} .$

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Similar questions

Q. The common difference for the arithmetic progression

3 + 2 \sqrt{2}, 3 + 4 \sqrt{2}, 3 + 6 \sqrt{2}, 3 + 8 \sqrt{2}

Find the common difference of the following arithmetic progression.
$3 + 2 \sqrt{2}, 3 + 4 \sqrt{2}, 3 + 6 \sqrt{2}, 3 + 8 \sqrt{2}$

Q. Find the common difference of the following AP:

3.3 + \sqrt{2,} 3 + 2 \sqrt{2}, 3 + 3 \sqrt{2}

Question 4 (v)
Which of the following are APs? If they form an A.P. find the common difference d and write three more terms.
(v) $3, 3 + \sqrt{2}, 3 + 2 \sqrt{2}, 3 + 3 \sqrt{2}$

Q. Find out which of the following sequence are arithmetic progression. For those which are arithmetic progression, find out the common difference.

\frac{1}{2}, \frac{1}{4}, \frac{1}{6}, \frac{1}{8}, . . . . . .

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Find the common difference for the arithmetic progression 3+2√2, 3+4√2, 3+6√2, 3+8√2.

The correct option is D 2√2Common difference (d) of an AP is the difference between any two consecutive terms of the AP. Thus, the common difference of the given AP is d=(3+4√2)−(3+2√2)=2√2.

Find the common difference for the arithmetic progression $3 + 2 \sqrt{2}, 3 + 4 \sqrt{2}, 3 + 6 \sqrt{2}, 3 + 8 \sqrt{2}$ .

The correct option is D $2 \sqrt{2}$
Common difference ( $d$ ) of an AP is the difference between any two consecutive terms of the AP.
Thus, the common difference of the given AP is
$d = (3 + 4 \sqrt{2}) - (3 + 2 \sqrt{2}) = 2 \sqrt{2} .$