Find the common difference of the following arithmetic progression.
$3 + 2 \sqrt{2}, 3 + 4 \sqrt{2}, 3 + 6 \sqrt{2}, 3 + 8 \sqrt{2}$

$3 + \sqrt{2}$

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$3$

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$\sqrt{2}$

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$2 \sqrt{2}$

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Solution

The correct option is D
$2 \sqrt{2}$

Common difference is the difference between two consecutive terms in an arithmetic sequence.
$(3 + 4 \sqrt{2}) - (3 + 2 \sqrt{2}) = 2 \sqrt{2}$
$(3 + 6 \sqrt{2}) - (3 + 4 \sqrt{2}) = 2 \sqrt{2}$
$(3 + 8 \sqrt{2}) - (3 + 6 \sqrt{2}) = 2 \sqrt{2}$

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Similar questions

Q. Find the common difference for the arithmetic progression

3 + 2 \sqrt{2}, 3 + 4 \sqrt{2}, 3 + 6 \sqrt{2}, 3 + 8 \sqrt{2}

Q. The common difference for the arithmetic progression

3 + 2 \sqrt{2}, 3 + 4 \sqrt{2}, 3 + 6 \sqrt{2}, 3 + 8 \sqrt{2}

Q. Find the common difference of the following AP:

3.3 + \sqrt{2,} 3 + 2 \sqrt{2}, 3 + 3 \sqrt{2}

Question 4 (v)
Which of the following are APs? If they form an A.P. find the common difference d and write three more terms.
(v) $3, 3 + \sqrt{2}, 3 + 2 \sqrt{2}, 3 + 3 \sqrt{2}$

Question 4 (v)
Which of the following are APs? If they form an A.P. find the common difference d and write three more terms.
(v) $3, 3 + \sqrt{2}, 3 + 2 \sqrt{2}, 3 + 3 \sqrt{2}$

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Find the common difference of the following arithmetic progression. 3+2√2, 3+4√2, 3+6√2, 3+8√2

The correct option is D 2√2 Common difference is the difference between two consecutive terms in an arithmetic sequence. (3+4√2)−(3+2√2)=2√2 (3+6√2)−(3+4√2)=2√2 (3+8√2)−(3+6√2)=2√2

Find the common difference of the following arithmetic progression.
$3 + 2 \sqrt{2}, 3 + 4 \sqrt{2}, 3 + 6 \sqrt{2}, 3 + 8 \sqrt{2}$

The correct option is D
$2 \sqrt{2}$

Common difference is the difference between two consecutive terms in an arithmetic sequence.
$(3 + 4 \sqrt{2}) - (3 + 2 \sqrt{2}) = 2 \sqrt{2}$
$(3 + 6 \sqrt{2}) - (3 + 4 \sqrt{2}) = 2 \sqrt{2}$
$(3 + 8 \sqrt{2}) - (3 + 6 \sqrt{2}) = 2 \sqrt{2}$