Question

Find the common difference of the given AP: $\frac{3}{4},1,1\frac{1}{4}$.........

• A. $-\frac{1}{4}$
• B. $\frac{1}{3}$
• C. $\frac{1}{2}$
• D. $\frac{1}{4}$

Answer 1

The correct option is D

$\frac{1}{4}$

When the Series are in A.P, the difference between the consecutive terms is the common difference.

In the given set of numbers,

first term $a_1=\frac{3}{4}$

second term $a_2=1$

third term $a_3=1\frac{1}{4}$

$\therefore$ Common difference is:
$a_2-a_1=1-\frac{3}{4}=\frac{4-3}{4}=\frac{1}{4}$

(or)

$a_3-a_2=1\frac{1}{4}-1=\frac{5}{4}-1=\frac{5-4}{4}=\frac{1}{4}$