Question

find the common factor:
1- 15(xy+4) , 12(xy+4)²

Answer 1

$$\begin{gathered} 15\left(\mathrm{xy}+4\right)=3\times 5\times \left(\mathrm{xy}+4\right) \\ 12{\left(\mathrm{xy}+4\right)}^2=2\times 2\times 3\left(\mathrm{xy}+4\right)\left(\mathrm{xy}+4\right) \\ \mathrm{Common}\mathrm{factor}=3\times \left(\mathrm{xy}+4\right) \end{gathered}$$