Given: 35a2b4+21ab3+7a2b+49a2b6
To find: Common factor
In the giben expression, the minimum power of a is 1 and the minimum power ofb is 1.
Also, the common factor among the coefficients of the terms in the given expression is 7.
Hence,
35a2b4+21ab3+7a2b+49a2b6=7ab(5ab3+3b2+a+7ab5)
So the common factor for the given expression is 7ab