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Question

Find the common factors of :
  1. 15 and 25
  2. 56 and 120
  3. 8,12 and 48

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Solution

(1) HCF of 15 and 25
15=3×5
25=5×5
So, HCF=5

(2) HCF of 56 and 120
56=2×2×2×7
120=2×2×2××3×5
So, HCF=2×2×2=8

(3) HCF of 8,12 and 48
8=2×2×2
20=2×2×3
48=2×2×2×2×3
So, HCF=2×2=4

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