In the given G.P., we have t1 = 2, t2 = –6 and t3 = 18.
Thus, we have the first term, i.e., a = t1 = 2, and the common ratio, i.e., .
We know that the nth term of the G.P. is tn = arn – 1.
By taking a = 2, r = –3 and n = 7, we have:
t7 = (2)(–3)7 – 1
t7 = (2)(–3)6
t7 = 2 × 729 = 1458
Thus, the common ratio of the given G.P. is –3 and the 7th term is 1458.