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Question

Find the common ratio and the general term of the following geometric sequences.
25,625,18125,....

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Solution

Given sequence is a geometric sequence.
The common ratio is given by r=t2t1=t3t2=.....
Thus, r=62525=35.
The first term of the sequence is 25.
So, the general term of the sequence is
tn=arn1,n=1,2,3,....
tn=25(35)n1,n=1,2,3,.....

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