Find the common root of $x^{2} - 15 x + 56 = 0 x^{2} - 17 x + 72 = 0$

Open in App

Solution

$x^{2} - 15 x + 56 = 0 x^{2} - 7 x - 8 x + 56 = 0 x (x - 7) - 8 (x - 7) = 0 (x - 7) (x - 8) = 0 x = 7, 8 x^{2} - 17 x + 72 = 0 x^{2} - 8 x - 9 x + 72 = 0 x (x - 8) - 9 (x - 8) = 0 (x - 9) (x - 8) = 0 x = 8, 9$
So the common root is $8$

Suggest Corrections

Similar questions

x^{2} - 3 x + 2 = 0 x^{2} - 7 x + 10 = 0

x^{2} - 12 x + 32 = 0 x^{2} - 9 x + 20 = 0

x^{2} - 9 x + 20 = 0 x^{2} - 12 x + 35 = 0

4 x^{4} + 12 x^{3} - x^{2} - 15 x = 0, 6 x^{4} + 13 x^{3} - 4 x^{2} - 15 x = 0

192

x^{2} - 15 x + 56 = 0.

Join BYJU'S Learning Program