Find the common root of $x^{2} - 4 x + 5 = 0$ an $x^{2} - 12 x + 35 = 0$

Open in App

Solution

$x^{2} - 6 x + 5 = 0 x^{2} - 5 x - x + 5 = 0 x (x - 5) - 1 (x - 5) = 0 (x - 5) (x - 1) = 0 x = 1, 5$ and $x^{2} - 12 x + 35 = 0 x^{2} - 5 x - 7 x + 35 = 0 x (x - 5) - 7 (x - 5) = 0 (x - 7) (x - 5) = 0 x = 5, 7$
So the common root is $5$

Suggest Corrections

Similar questions

x^{2} - 9 x + 20 = 0 x^{2} - 12 x + 35 = 0

x^{2} - 6 x + 5 = 0

x^{2} - 12 x + p = 0

x^{2} - 12 x + 35 = 0

x^{2} + y^{2} - 12 x + 35 = 0

x^{2} + y^{2} + 4 x + 3 = 0

x^{2} + 12 x + 35 = 0

Join BYJU'S Learning Program