Find the complement of an angle whose measure is $3 x - 8^{o}$ .

3 x - 98^{o}

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82^{o} - 3 x

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98^{o} - 3 x

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3 x - 82^{o}

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Solution

The correct option is C $98^{o} - 3 x$
Complement of an angle $A = 90^{o} - A$
So, complement of angle $3 x - 8^{o} = 90^{o} - (3 x - 8^{o}) = 98^{o} - 3 x$

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