Question

Find the complement of: $\frac{1}{2}$ of ${40}^0$.

Answer 1

We know that, if two angles are complementary, then their sum is ${90}^o$.

Then, the complement angle of $\frac{1}{2}$ of ${40}^o$ is,

$={90}^o-(\frac{1}{2}\times {40}^o)$

$={90}^o-{20}^o$

$={70}^o$.

Therefore, the complement angle of $\frac{1}{2}$ of ${40}^o$ is ${70}^o$.