Find the complement of the angle $63^{o}$

70^{\circ}

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27^{\circ}

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45^{\circ}

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62^{\circ} 32^{'}

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Solution

The correct option is B $27^{\circ}$
We know, two angles are complementary when they add up to $90^{o} .$

Given, measure of one complementary angle is $63^{o} .$

$\Rightarrow$ Measure of other complementary angle $= 90^{o} - 63^{o}$ $= 27^{o} .$

$∴$ Measure of a complementary angle of $63^{o} = 27^{o}$ .
Hence, option $B$ is correct.

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(b) The supplement of which angle is the complement of $70^{\circ}$ ?

Question 87

If the complement of an angle is $62^{\circ},$ then find its supplement.

Question 100(ii)

Construct a frequency distribution table for the following weights (in grams) of 35 mangoes, using the equal class intervals, one of them is 40-45 (45 not included):
30, 40, 45, 32, 43, 50, 55, 62, 70, 70, 61, 62, 53, 52, 50, 42, 35, 37,
53, 55, 65, 70, 73, 74, 45, 46, 58, 59, 60, 62, 74, 34, 35, 70, 68
Which weight group has the highest frequency ?

Question 100(i)

Q. If the complement of an angle is

27^{\circ}

, then find its supplement.

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Find the complement of the angle 63o

The correct option is B 27∘We know, two angles are complementary when they add up to 90o. Given, measure of one complementary angle is 63o. ⇒ Measure of other complementary angle =90o−63o =27o. ∴ Measure of a complementary angle of 63o=27o.Hence, option B is correct.

Find the complement of the angle $63^{o}$