Question

Find the complementary angle of $22{\frac{1}{2}}^o$.

Answer 1

We know, two angles are said to be complementary, if the sum of their measures is ${90}^{\circ }.$

The given angle is $22{\frac{1}{2}}^{\circ }=\frac{45}{2}$.

Let the measure of its complement be $x^{\circ }.$

Then,

$⟹$ $x+{\frac{45}{2}}^o={90}^o$

$⟹x={90}^o-{\frac{45}{2}}^o$

$⟹x={\frac{135}{2}}^o=67{\frac{1}{2}}^{\circ }$

Hence, the complement of the given angle measures $67{\frac{1}{2}}^{\circ }$