Question

Find the complex conjugate $($in the from $A+iB$ $)$ of $\frac{(8-3i)(6-i)}{2-2i}$

Answer 1

$z=\frac{(8-3i)(6-i)}{2-2i}$

$=\frac{48-8i-18i-3}{2-2i}$

$=\frac{45-26i}{2-2i}$

$=\frac{(45-26i)}{(2-2i)}\times \frac{(2+2i)}{(2+2i)}$

$=\frac{90+90i-52i+52}{4+4}$

$=\frac{142+38i}{8}$

$z=\frac{142}{8}+\frac{38}{8}i$

$=\frac{71}{4}+\frac{19}{4}i$

$\overline{z}=\frac{71}{4}-\frac{19}{4}i$ (conjugate of given complex no.)